Leetcode: Permutations
Problem Description
Problem definition is taken from leetcode.
Given an array nums of distinct integers, return all the possible permutations. You can return the answer in any order.
Example 1
Input: nums = [1,2,3]
Output: [[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]
Example 2
Input: nums = [0,1]
Output: [[0,1],[1,0]]
Iterative Solution
class Solution:
def permute(self, nums: List[int]) -> List[List[int]]:
return self.permuteSeq(nums)
def permuteSeq(self, nums):
perms=[[]]
for n in nums:
new_perms = []
for perm in perms:
for i in range(len(perm)+1):
new_perms.append(perm[:i]+[n]+perm[i:])
perms = new_perms
return perms
Recursive Solution
class Solution:
def permute(self, nums: List[int]) -> List[List[int]]:
results=[]
self.permuteRec(results, nums, [])
return results
def permuteRec(self, results, nums, perm):
if nums:
for idx in range(len(nums)):
self.permuteRec(results, nums[:idx]+nums[idx+1:], perm+[nums[idx]])
else:
results.append(perm)